如圖所示,我輸出了0_degree那條線的數(shù)據(jù),如下:
;hJ/t/7 CHART: receiver_85 intensityMesh 0_degrees metric luminous intensity intensitySlices
mYs->mg1 ## Location: X(t), Y(t), Z(t); Point count; Coordinates displayed
J;]@?( SERIES: 0*t + 12 180*t v 15 YZ
Qre&N_ ## t parameter, value at t
h/y} ## Values at t = 0, and t = 1 are on the sampling mesh boundary.
BrH`:Dw 0.0333333 0.00000 # 12 6
cd%g]T)#1 0.1 0.00000 # 12 18
. L6@Rs 0.166667 0.00000 # 12 30
J$ih|nP 0.233333 0.00000 # 12 42
L5N{ie_ 0.3 0.00000 # 12 54
bJMcI8` 0.366667 0.00000 # 12 66
Q9'p3"yoE 0.433333 0.00000 # 12 78
k~EPVJh" 0.5 0.00000 # 12 90
kviSQM2 0.566667 0.00295 # 12 102
@IKe<{w 0.633333 0.04428 # 12 114
aZ:?(u] 0.7 0.19644 # 12 126
!{ )AV/\D 0.766667 0.32061 # 12 138
lL+^n~g 0.833333 0.34684 # 12 150
7|eSvC 0.9 0.35269 # 12 162
(w:ACJ[[ 0.966667 0.35743 # 12 174
*gpD4c7A\
.nY6[2am 5qB=@O]|G; 數(shù)據(jù)一共5列,第一列是發(fā)光強(qiáng)度,最后一列為緯度,這個(gè)我看出來(lái)了,其它的就不知道了,包括那一列#號(hào)!
~E|V{z% 請(qǐng)高手指點(diǎn)!
YaZ"&i 另外90_degree那條線和0_degree那條線對(duì)應(yīng)的剖面是哪里呢,兩個(gè)剖面是正交的嗎?