小弟不是學(xué)光學(xué)的，所以想請(qǐng)各位大俠指點(diǎn)啊！謝謝啦 ZV4' |q  
就是我用ansys計(jì)算出了鏡面的面型的數(shù)據(jù)，怎樣可以得到zernike多項(xiàng)式的系數(shù)，然后用zemax各階得到像差！謝謝啦！ NWwtq&pz2  

可以用matlab編程，用zernike多項(xiàng)式進(jìn)行波面擬合，求出zernike多項(xiàng)式的系數(shù)，擬合的算法有很多種，最簡(jiǎn)單的是最小二乘法，你可以查下相關(guān)資料，挺簡(jiǎn)單的

澤尼克多項(xiàng)式的前9項(xiàng)對(duì)應(yīng)象差的

非常感謝啊，我手上也有zernike多項(xiàng)式的擬合的源程序，也不知道對(duì)不對(duì)，不怎么會(huì)有 &-Er n/[  
function z = zernfun(n,m,r,theta,nflag) 0%j;yzQ<  
%ZERNFUN Zernike functions of order N and frequency M on the unit circle. 1+c(G?Ava  
%   Z = ZERNFUN(N,M,R,THETA) returns the Zernike functions of order N g7f%(W2dd  
%   and angular frequency M, evaluated at positions (R,THETA) on the ]=<@G.[=  
%   unit circle.  N is a vector of positive integers (including 0), and 4GA-dtyV&  
%   M is a vector with the same number of elements as N.  Each element a3IB, dr5P  
%   k of M must be a positive integer, with possible values M(k) = -N(k) irj}:f;!eF  
%   to +N(k) in steps of 2.  R is a vector of numbers between 0 and 1, :S6 <v0`Z  
%   and THETA is a vector of angles.  R and THETA must have the same o;I86dI6C  
%   length.  The output Z is a matrix with one column for every (N,M) 
6.=1k  
%   pair, and one row for every (R,THETA) pair. T7_rnEOO   
% <{Wa[1D  
%   Z = ZERNFUN(N,M,R,THETA,'norm') returns the normalized Zernike I3b-uEHev  
%   functions.  The normalization factor sqrt((2-delta(m,0))*(n+1)/pi), lfd{O7 汾阳市| 大化| 仲巴县| 磴口县| 绩溪县| 图们市| 瑞金市| 长阳| 图们市| 望城县| 敦煌市| 承德市| 城固县| 南木林县| 京山县| 榕江县| 烟台市| 高密市| 庆城县| 郎溪县| 资讯| 南漳县| 阿拉善左旗| 茂名市| 武平县| 平顶山市| 红原县| 博兴县| 囊谦县| 阿拉善右旗| 剑河县| 天台县| 孝义市| 沙坪坝区| 彭州市| 迁安市| 化隆| 贵德县| 闽清县| 彭山县| 扎鲁特旗|